Integrand size = 27, antiderivative size = 113 \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}}+\frac {8 \sqrt {d^2-e^2 x^2}}{3 e^5}+\frac {d \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e^5} \]
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Time = 0.06 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {864, 833, 655, 223, 209} \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {d \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e^5}+\frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {8 \sqrt {d^2-e^2 x^2}}{3 e^5}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}} \]
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Rule 209
Rule 223
Rule 655
Rule 833
Rule 864
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^4 (d-e x)}{\left (d^2-e^2 x^2\right )^{5/2}} \, dx \\ & = \frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {\int \frac {x^2 \left (3 d^3-4 d^2 e x\right )}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx}{3 d^2 e^2} \\ & = \frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}}+\frac {\int \frac {3 d^5-8 d^4 e x}{\sqrt {d^2-e^2 x^2}} \, dx}{3 d^4 e^4} \\ & = \frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}}+\frac {8 \sqrt {d^2-e^2 x^2}}{3 e^5}+\frac {d \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx}{e^4} \\ & = \frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}}+\frac {8 \sqrt {d^2-e^2 x^2}}{3 e^5}+\frac {d \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )}{e^4} \\ & = \frac {x^3 (d-e x)}{3 e^2 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {x (3 d-4 e x)}{3 e^4 \sqrt {d^2-e^2 x^2}}+\frac {8 \sqrt {d^2-e^2 x^2}}{3 e^5}+\frac {d \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{e^5} \\ \end{align*}
Time = 0.31 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.93 \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {\frac {\sqrt {d^2-e^2 x^2} \left (8 d^3+5 d^2 e x-7 d e^2 x^2-3 e^3 x^3\right )}{(d-e x) (d+e x)^2}-6 d \arctan \left (\frac {e x}{\sqrt {d^2}-\sqrt {d^2-e^2 x^2}}\right )}{3 e^5} \]
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Time = 0.41 (sec) , antiderivative size = 186, normalized size of antiderivative = 1.65
method | result | size |
risch | \(\frac {\sqrt {-e^{2} x^{2}+d^{2}}}{e^{5}}+\frac {d \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{e^{4} \sqrt {e^{2}}}+\frac {19 d \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}{12 e^{6} \left (x +\frac {d}{e}\right )}-\frac {d \sqrt {-\left (x -\frac {d}{e}\right )^{2} e^{2}-2 d e \left (x -\frac {d}{e}\right )}}{4 e^{6} \left (x -\frac {d}{e}\right )}-\frac {d^{2} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}{6 e^{7} \left (x +\frac {d}{e}\right )^{2}}\) | \(186\) |
default | \(\frac {-\frac {x^{2}}{e^{2} \sqrt {-e^{2} x^{2}+d^{2}}}+\frac {2 d^{2}}{e^{4} \sqrt {-e^{2} x^{2}+d^{2}}}}{e}+\frac {d^{2}}{e^{5} \sqrt {-e^{2} x^{2}+d^{2}}}-\frac {d x}{e^{4} \sqrt {-e^{2} x^{2}+d^{2}}}-\frac {d \left (\frac {x}{e^{2} \sqrt {-e^{2} x^{2}+d^{2}}}-\frac {\arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{e^{2} \sqrt {e^{2}}}\right )}{e^{2}}+\frac {d^{4} \left (-\frac {1}{3 d e \left (x +\frac {d}{e}\right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}-\frac {-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e}{3 e \,d^{3} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{e^{5}}\) | \(257\) |
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Time = 0.26 (sec) , antiderivative size = 175, normalized size of antiderivative = 1.55 \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {8 \, d e^{3} x^{3} + 8 \, d^{2} e^{2} x^{2} - 8 \, d^{3} e x - 8 \, d^{4} - 6 \, {\left (d e^{3} x^{3} + d^{2} e^{2} x^{2} - d^{3} e x - d^{4}\right )} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (3 \, e^{3} x^{3} + 7 \, d e^{2} x^{2} - 5 \, d^{2} e x - 8 \, d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{3 \, {\left (e^{8} x^{3} + d e^{7} x^{2} - d^{2} e^{6} x - d^{3} e^{5}\right )}} \]
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\[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\int \frac {x^{4}}{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {3}{2}} \left (d + e x\right )}\, dx \]
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Time = 0.29 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.10 \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=-\frac {d^{3}}{3 \, {\left (\sqrt {-e^{2} x^{2} + d^{2}} e^{6} x + \sqrt {-e^{2} x^{2} + d^{2}} d e^{5}\right )}} - \frac {x^{2}}{\sqrt {-e^{2} x^{2} + d^{2}} e^{3}} - \frac {4 \, d x}{3 \, \sqrt {-e^{2} x^{2} + d^{2}} e^{4}} + \frac {d \arcsin \left (\frac {e x}{d}\right )}{e^{5}} + \frac {3 \, d^{2}}{\sqrt {-e^{2} x^{2} + d^{2}} e^{5}} \]
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\[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\int { \frac {x^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} {\left (e x + d\right )}} \,d x } \]
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Timed out. \[ \int \frac {x^4}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\int \frac {x^4}{{\left (d^2-e^2\,x^2\right )}^{3/2}\,\left (d+e\,x\right )} \,d x \]
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